Myles Garrett named AFC Defensive Player of the Week (11.27.24)

For Immediate Release

Nov. 27, 2024

Myles Garrett named AFC Defensive Player of the Week

BEREA, Ohio – Cleveland Browns DE Myles Garrett has earned AFC Defensive Player of the Week for games played Nov. 21-25 (Week 12), the National Football League announced Wednesday.

Garrett recorded five tackles, three sacks and one forced fumble during the Browns 24-19 victory against the Steelers. All three of his sacks made a big impact on the game as the first was on third down, forcing a longer field goal attempt, which was missed. The second sack also forced a fumble that resulted in a takeaway, which led to a Browns field goal. His third sack came on a third-down play to end the first half. Garrett is the only NFL player to record multiple games with at least three sacks this season. He increased his season total to 10 sacks (tied for third in the NFL) and he is only NFL player to record at least 10 sacks in each of the past seven seasons (2018-24).

Garrett has won four career weekly league awards as he also earned the honors in 2023 (Week 7), 2021 (Week 3) and 2020 (Week 4). He joins Jameis Winston (AFC Offensive Player of the Week for Week 8) as Browns to earn the honor this season.

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